12z^2-4=8z

Solution for 12z^2-4=8z equation:

12z^2-4=8z

We move all terms to the left:

12z^2-4-(8z)=0

a = 12; b = -8; c = -4;
Δ = b2-4ac
Δ = -82-4·12·(-4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16}{2*12}=\frac{-8}{24}
=-1/3
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16}{2*12}=\frac{24}{24}
=1
$